University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 7 - Section 7.2 - Exponential Change and Separable Differential Equations - Exercises - Page 410: 28


$\approx 92.1 s$

Work Step by Step

Given: When the voltage is 10% of its original value, that is, $V =0.1 V_0$ Now, we have $V(t)=V_0e^{-t/40}$ ...(1) This implies that $0.1 V_0=V_0e^{-t/40} \implies t=-40 (\ln (0.1)) $ This implies that $t \approx 92.1 s$ Hence, $t \approx 92.1 s$
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