Chapter 7 - Section 7.2 - Exponential Change and Separable Differential Equations - Exercises - Page 410: 25

$54.88$gm

Given: $y_0=100$ The exponential growth can be written as: $\dfrac{dy}{dt}=-0.6y$ Re-arrange the given equation as follows: Then, $y=y_0e^{-0.6 t}$ Now, when t = 1 hour Then $y=(100)e^{-0.6 t} \implies y=(100) e^{-0.6}$ Hence, $y \approx 54.88$gm