## University Calculus: Early Transcendentals (3rd Edition)

$54.88$gm
Given: $y_0=100$ The exponential growth can be written as: $\dfrac{dy}{dt}=-0.6y$ Re-arrange the given equation as follows: Then, $y=y_0e^{-0.6 t}$ Now, when t = 1 hour Then $y=(100)e^{-0.6 t} \implies y=(100) e^{-0.6}$ Hence, $y \approx 54.88$gm