University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Practice Exercises - Page 390: 5

Answer

$\dfrac{ 72 \pi }{35}$

Work Step by Step

We need to integrate the integral as shown below: $Volume = \int_{0}^{4} \pi (\sqrt x- \dfrac{x^2}{8}) ^2 dx \\=\pi [\dfrac{x^2}{2}-\dfrac{x^{(7/2)}}{14} +\dfrac{x^5}{320}]_0^4 \\=\pi (8-\dfrac{64}{7} +\dfrac{16}{5}) \\=\dfrac{ 72 \pi }{35}$
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