University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Practice Exercises - Page 390: 3



Work Step by Step

We need to integrate the integral as shown below: $I=\pi \int_{(\pi/4)}^{(5 \pi/4)} (\sin x -\cos x)^2 dx \\=\pi \int_{(\pi/4)}^{(5 \pi/4)} (1- \sin (2x)) dx \\=\pi [x+\dfrac{\cos (2x) }{2}] _{\pi/4}^{5 \pi/4} \\=\pi^2$
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