University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises - Page 300: 40



Work Step by Step

Here, we have $f(x)=2x$ Then, $\Sigma_{i=1}^n (\dfrac{6}{n}) c_i=(\dfrac{1}{n}) \Sigma_{i=1}^n \dfrac{18i}{n^2}$ or, $\dfrac{18n(n+2)}{2n^2})=\dfrac{9(n+1)}{n}=9$
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