#### Answer

$1.1$

#### Work Step by Step

We are given: $2,1.6,0.5,0,0.8,1$
We need to split the given points in the intervals as follows:
For sub-interval $[1.6,2]$, we have $2-1.6=0.4$;
For sub-interval $[0.5,1.6]$, we have $1.6-0.5=1.1$
For sub-interval $[0,0.5]$, we have $0.5-0=0.5$
For sub-interval $[0.8,0]$, we have $0.8-0=0.8$
For sub-interval $[0.8,1]$, we have $1-0.8=0.2$
Thus, the norm of the partition will be the widest interval: $1.1$