Answer
$\dfrac{32}{3}$
Work Step by Step
We know that $\int x^{n} dx=\dfrac{x^{n+1}}{n+1}+C$
where $C$ is a constant of proportionality.
$\int_{-2}^{2} (4-y^2) dy=[4y-y^3/3]_{-2}^{2}$
or, $=4(2+2)-\dfrac{1}{3}(8+8)$
or $=\dfrac{32}{3}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Practice Exercises - Page 342: 20
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