Answer
$\frac{\theta^{2-\pi}}{2-\pi}+C$
Work Step by Step
Calculate the anti-derivative.
we know that: $\int x^{n} dx=\dfrac{x^{n+1}}{n+1}+c$
where $c$ is a constant of proportionality.
Then $\int \theta^{1-\pi} d\theta=\dfrac{\theta^{1-\pi+1}}{1-\pi+1}+C=\frac{\theta^{2-\pi}}{2-\pi}+C$
