University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.9 - Inverse Trigonometric Functions - Exercises - Page 181: 9


$\frac{\sqrt 2}{2}$

Work Step by Step

The given problem can be solved as: $sin({cos^{-1}(\frac{\sqrt 2}{2})})=sin ( \frac{\pi}{4})$ or, $sin ( \frac{\pi}{4})=\frac{\sqrt 2}{2}$ Hence. the final answer is: $\frac{\sqrt 2}{2}$
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