University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.9 - Inverse Trigonometric Functions - Exercises - Page 181: 7

Answer

a) Need to calculate the value of inverse trigonometric funtion . $sec^{-1}(-\sqrt 2)=\frac{3\pi}{4}$ b) Need to calculate the value of inverse trigonometric funtion. $sec^{-1}(\frac{2}{\sqrt 3})=(\frac{\pi}{6})$ c) Need to calculate the value of inverse trigonometric funtion. $sec^{-1}(-2)=\frac{2\pi}{3}$

Work Step by Step

a) Need to calculate the value of inverse trigonometric funtion . $sec^{-1}(-\sqrt 2)=\frac{3\pi}{4}$ b) Need to calculate the value of inverse trigonometric funtion. $sec^{-1}(\frac{2}{\sqrt 3})=(\frac{\pi}{6})$ c) Need to calculate the value of inverse trigonometric funtion. $sec^{-1}(-2)=\frac{2\pi}{3}$
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