## University Calculus: Early Transcendentals (3rd Edition)

a) Need to calculate the value of inverse trigonometric funtion . $sec^{-1}(-\sqrt 2)=\frac{3\pi}{4}$ b) Need to calculate the value of inverse trigonometric funtion. $sec^{-1}(\frac{2}{\sqrt 3})=(\frac{\pi}{6})$ c) Need to calculate the value of inverse trigonometric funtion. $sec^{-1}(-2)=\frac{2\pi}{3}$
a) Need to calculate the value of inverse trigonometric funtion . $sec^{-1}(-\sqrt 2)=\frac{3\pi}{4}$ b) Need to calculate the value of inverse trigonometric funtion. $sec^{-1}(\frac{2}{\sqrt 3})=(\frac{\pi}{6})$ c) Need to calculate the value of inverse trigonometric funtion. $sec^{-1}(-2)=\frac{2\pi}{3}$