Answer
$$y'=\frac{2}{t}$$
Work Step by Step
$$y=\ln(t^2)$$
Recall the Derivative Rule for Natural Logarithm: $$\frac{d}{dx}(\ln u)=\frac{1}{u}\frac{du}{dx}$$
Therefore, we have $$y'=\frac{1}{t^2}(t^2)'=\frac{2t}{t^2}=\frac{2}{t}$$
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