University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.6 - The Chain Rule - Exercises - Page 159: 90

Answer

$dy/dt=3$

Work Step by Step

We have $y=x^2+7x-5$ and $dx/dt=1/3$ According to the Chain Rule: $$\frac{dy}{dt}=\frac{dy}{dx}\frac{dx}{dt}=\frac{1}{3}\frac{dy}{dx}$$ $dy/dx$ refers to the derivative of $y$, which is $y'=2x+7$. That means, $$\frac{dy}{dt}=\frac{2x+7}{3}$$ For $x=1$: $$\frac{dy}{dt}=\frac{2\times1+7}{3}=3$$
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