University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.5 - Derivatives of Trigonometric Functions - Exercises - Page 152: 47

Answer

$$\lim_{x\to2}\sin\Big(\frac{1}{x}-\frac{1}{2}\Big)=0$$

Work Step by Step

$$A=\lim_{x\to2}\sin\Big(\frac{1}{x}-\frac{1}{2}\Big)$$ $$A=\sin\Big(\frac{1}{2}-\frac{1}{2}\Big)$$ $$A=\sin0=0$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.