University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.2 - The Derivative as a Function - Exercises: 11

Answer

$p'(q) = \frac{3}{2}q^{\frac{1}{2}}$

Work Step by Step

$p(q) =q^{\frac{3}{2}}$ So, $p'(q) = \frac{3}{2}q^{\frac{3}{2}-1}$ $p'(q) = \frac{3}{2}q^{\frac{1}{2}}$
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