Answer
$p'(q) = \frac{3}{2}q^{\frac{1}{2}}$
Work Step by Step
$p(q) =q^{\frac{3}{2}}$
So,
$p'(q) = \frac{3}{2}q^{\frac{3}{2}-1}$
$p'(q) = \frac{3}{2}q^{\frac{1}{2}}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.2 - The Derivative as a Function - Exercises - Page 124: 11
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