#### Answer

$6$
$0$
$-2$

#### Work Step by Step

$f(x)=4-x^2$, therefore $f'(x)=0-2x$
$f'(-3)=0-2\times(-3)=6$
$f'(0)=0-2\times(0)=0$
$f'(1)=0-2\times(1)=-2$

Published by
Pearson

ISBN 10:
0321999584

ISBN 13:
978-0-32199-958-0

$6$
$0$
$-2$

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