## University Calculus: Early Transcendentals (3rd Edition)

We have: $y=x^2$ $\tan\theta=\frac{y}{x}$ Using the Pythagorean Theorem: $\tan\theta =\frac{x^2}{x}=x$ and given $dx=10\frac{m}{sec}$ on differentiating the above: $\sec^2\theta d\theta=dx$ $d\theta=\frac{dx}{ \sec^2\theta}=\frac{10}{(\frac{\sqrt(90)}{3})^2}=1 rad/sec$ Thus, the final answer is: 1 rad/sec