University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.1 - Tangents and the Derivative at a Point - Exercises - Page 117: 3

Answer

The estimated slope of the curve at $P_1$ is $2.5$. The estimated slope of the curve at $P_2$ is $-1$.

Work Step by Step

To estimate the slope $m$ of the curve at point $P(a,b)$ without the equation of the function, we find another point $Q(c, d)$ as near to $P$ as possible in the graph, then the slope of the curve will approximately be equal with the slope of $PQ$: $$m=\frac{d-b}{c-a}$$ 1) Find the slope $m_1$ of the curve at $P_1(0.4,1.1)$. In the graph, we see that very near to $P_1$, there is a point $Q(0.2,0.6)$. By calculating the slope of $P_1Q$, we will have the estimated slope $m_1$ of the curve at $P_1$: $$m_1=\frac{1.1-0.6}{0.4-0.2}=\frac{0.5}{0.2}=2.5$$ 2) Find the slope $m_2$ of the curve at $P_2(1.9,1.3)$: In the graph, we see that very near to $P_2$, there is this point $R(1.7,1.5)$. By calculating the slope of $P_2R$, we will have the estimated slope $m_2$ of the curve at $P_2$: $$m_2=\frac{1.5-1.3}{1.7-1.9}=\frac{0.2}{-0.2}=-1$$
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