#### Answer

$\delta=9/25$

#### Work Step by Step

Find a $\delta\gt0$ such that for all $x$ $$0\lt |x-(-1)|\lt\delta\Rightarrow|f(x)-2|\lt0.5$$
Looking at the graphs, we can see that for values of $f(x)$ to be restricted between $1.5$ and $2.5$ (which means $|f(x)-2|\lt0.5$), $x$ must be placed between $-\frac{16}{9}$ and $-\frac{16}{25}$.
The graph also shows that the endpoint $-\frac{16}{25}$ is nearer to $-1$ than $-\frac{16}{25}$, so we would take its distance from $-1$ to $-\frac{16}{25}$ to be $\delta$.
$$\delta=|-1-(-\frac{16}{25})|=|-1+\frac{16}{25}|=|\frac{16-25}{25}|=|-\frac{9}{25}|=\frac{9}{25}$$
Therefore, $$0\lt |x-(-1)|\lt\frac{9}{25}\Rightarrow|f(x)-2|\lt0.5$$