Answer
We can guess here that $$\lim_{x\to0}\frac{2x^2}{3-3\cos x}=\frac{4}{3}$$
Work Step by Step
$$\lim_{x\to0}\frac{2x^2}{3-3\cos x}$$
(a) The graph is shown below.
(b) Looking at the graph, as $x\to0$, we see that $\frac{2x^2}{3-3\cos x}$ approaches as close as $\frac{4}{3}\approx1.3333333333...$
Therefore, we can guess here that $$\lim_{x\to0}\frac{2x^2}{3-3\cos x}=\frac{4}{3}$$
