Answer
We can guess here that $$\lim_{x\to-1}\frac{x^3-x^2-5x-3}{(x+1)^2}=-4$$
Work Step by Step
$$\lim_{x\to-1}\frac{x^3-x^2-5x-3}{(x+1)^2}$$
(a) The graph is shown below.
(b) Looking at the graph, as $x\to-1$, we see that $\frac{x^3-x^2-5x-3}{(x+1)^2}$ approaches as close as $-4$.
Therefore, we can guess here that $$\lim_{x\to-1}\frac{x^3-x^2-5x-3}{(x+1)^2}=-4$$
