University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises - Page 67: 52


(a) Quotient Rule. (b) Numerator: Root Rule - Denominator: Product Rule (c) Numerator: Constant Multiple Rule - Denominator: Difference Rule

Work Step by Step

(a) $$\lim_{x\to1}\frac{\sqrt{5h(x)}}{p(x)(4-r(x))}=\frac{\lim_{x\to1}\sqrt{5h(x)}}{\lim_{x\to1}(p(x)(4-r(x)))}$$ Here, $\lim_{x\to c}\frac{A}{B}=\frac{\lim_{x\to c}A}{\lim_{x\to c}B}$. This is Quotient Rule. (b) $$\frac{\lim_{x\to1}\sqrt{5h(x)}}{\lim_{x\to1}(p(x)(4-r(x)))}=\frac{\sqrt{\lim_{x\to1}5h(x)}}{\Big(\lim_{x\to1}p(x)\Big)\Big(\lim_{x\to1}(4-r(x))\Big)}$$ - Numerator: $\lim_{x\to c}\sqrt[n]A=\sqrt[n]{\lim_{x\to c}A}$. This is Root Rule. - Denominator: $\lim_{x\to c}(AB)=\lim_{x\to c}A\times\lim_{x\to c}B$. This is Product Rule. (c) $$\frac{\sqrt{\lim_{x\to1}5h(x)}}{\Big(\lim_{x\to1}p(x)\Big)\Big(\lim_{x\to1}(4-r(x))\Big)}=\frac{\sqrt{5\lim_{x\to1}h(x)}}{\Big(\lim_{x\to1}p(x)\Big)\Big(\lim_{x\to1}4-\lim_{x\to1}r(x)\Big)}$$ - Numerator: $\lim_{x\to c}(kA)=k\lim_{x\to c}A$. This is Constant Multiple Rule. - Denominator: Look at $\lim_{x\to1}(4-r(x))=\lim_{x\to1}4-\lim_{x\to1}r(x)$. This is Difference Rule.
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