Answer
$\lim\limits_{x \to 0}(2\sin{x} - 1) = -1$
Work Step by Step
$\lim\limits_{x \to 0}(2\sin{x} - 1) = 2\lim\limits_{x \to 0}\sin{x} -\lim\limits_{x \to 0}1 = 2(\sin{0}) -1= 0-1= -1$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises - Page 67: 43
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