#### Answer

$\lim\limits_{x \to 0}(2\sin{x} - 1) = -1$

#### Work Step by Step

$\lim\limits_{x \to 0}(2\sin{x} - 1) = 2\lim\limits_{x \to 0}\sin{x} -\lim\limits_{x \to 0}1 = 2(\sin{0}) -1= 0-1= -1$

Published by
Pearson

ISBN 10:
0321999584

ISBN 13:
978-0-32199-958-0

$\lim\limits_{x \to 0}(2\sin{x} - 1) = -1$

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