University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 16 - Section 16.1 - Solutions, Slope Fields, and Euler's Method - Exercises - Page 16-9: 38

Answer

$1.5574$

Work Step by Step

In order to determine the exact solution, isolate the x and y terms on one side and integrate both sides. $\int \dfrac{dy}{1+y^2}=\int dx$ ...(1) In order to determine the differential equation, we will have to take the derivative of the differential equation. Equation (2) gives: $\arctan (y)=x+c$ ...(2) Apply the initial conditions, to calculate the value of $c$ $\arctan (0)=0+c\implies c=0$ Now, the particular solution is as follows: $\arctan (y)=x$ or, $y=\tan x$ Thus, the exact solution is: $y(1)=\tan (1) \approx 1.5574$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.