University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 16 - Section 16.1 - Solutions, Slope Fields, and Euler's Method - Exercises - Page 16-9: 37

Answer

$1.5275$

Work Step by Step

In order to determine the exact solution, isolate the x and y terms on one side and integrate both sides. $\int y dy=\int \sqrt x dx$ ...(1) In order to determine the differential equation, we will have to take the derivative of the differential equation. Equation (2) gives: $(\dfrac{y^2}{2})=(2/3)x^{3/2}+c$ ...(2) Apply the initial conditions, to calculate the value of $c$ $\dfrac{(1)^2}{2}=(2/3)(0)^{3/2}+c\implies c=\dfrac{1}{2}$ Now, the particular solution is as follows: $(\dfrac{y^2}{2})=(\dfrac{2}{3})x^{3/2}+\dfrac{1}{2}$ or, $y=\sqrt {\dfrac{4}{3}(x^{3/2})+1}$ Thus, the exact solution is: $y(1)=\sqrt {\dfrac{4}{3}((1)^{3/2})+1} \approx 1.5275$
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