University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 15 - Section 15.7 - Stokes' Theorem - Exercises - Page 895: 5

Answer

$0$

Work Step by Step

Applying Stoke's Theorem, we have $\oint F \cdot dr=\iint _S (\nabla \times F) \cdot n d\sigma$ or, $\oint F \cdot dr=\int_{-1}^{1} \int_{-1}^{1} (2x-2y) dx dy$ or, $\int_{-1}^{1}[x^2-2xy]_{-1}^{1} =0$
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