University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 15 - Section 15.7 - Stokes' Theorem - Exercises - Page 895: 3

Answer

$\dfrac{-5}{6}$

Work Step by Step

As we are given that $F=yi+xzj+x^2k$ Applying Stoke's Theorem, we have $\oint F \cdot dr=\iint _S (\nabla \times F) \cdot n d\sigma$ or, $\oint F \cdot dr=\int_0^{1} \int_0^{1-y} (-xi-2xj+z-k) (\dfrac{(i+j+k)}{\sqrt 3}) \sqrt 3 dA $ or, $\int_0^{1}[-2x^2+y^2 ]_0^{1-y} =\dfrac{-5}{6}$
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