Answer
$\dfrac{-\pi}{2}$
Work Step by Step
Since, we have $\int_C F \cdot T ds-\int_C F. dr$
Now,
$\int_C y dx-x dy=\int_{0}^{\pi/2}(\sin t) (-\sin t dt) -\cos t (\cos t dt)$
$=\int_{0}^{\pi/2} (-1) dt$
or, $=\dfrac{-\pi}{2}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 15 - Section 15.2 - Vector Fields and Line Integrals: Work, Circulation, and Flux - Exercises - Page 838: 26
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