University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 14 - Section 14.4 - Double Integrals in Polar Form - Exercises - Page 777: 2

Answer

$\dfrac{-\pi}{2} \leq \theta \leq \dfrac{-\pi}{2}$ and $1\leq r\leq 4$

Work Step by Step

It can be seen that the radius goes from $1$ to $4$ and the angle $\theta$ goes from $\dfrac{-\pi}{2}$ to $\dfrac{\pi}{2}$. Therefore, the region described in polar coordinates is: $\dfrac{-\pi}{2} \leq \theta \leq \dfrac{-\pi}{2}$ and $1\leq r\leq 4$.
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