University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 14 - Section 14.4 - Double Integrals in Polar Form - Exercises - Page 777: 1

Answer

$\dfrac{\pi}{2} \leq \theta \leq 2 \pi$ and $0\leq r\leq 9$

Work Step by Step

It can be seen that the radius goes from $0$ to $9$ and the angle $\theta$ goes from $\dfrac{\pi}{2}$ to $2 \pi$. Therefore, the region described in polar coordinates is: $\dfrac{\pi}{2} \leq \theta \leq 2 \pi$ and $0\leq r\leq 9$.
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