Answer
$\dfrac{\pi}{2} \leq \theta \leq 2 \pi$ and $0\leq r\leq 9$
Work Step by Step
It can be seen that the radius goes from $0$ to $9$ and the angle $\theta$ goes from $\dfrac{\pi}{2}$ to $2 \pi$. Therefore, the region described in polar coordinates is:
$\dfrac{\pi}{2} \leq \theta \leq 2 \pi$ and $0\leq r\leq 9$.
