University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 12 - Practice Exercises - Page 674: 25

Answer

$\dfrac{\pi}{3}$

Work Step by Step

We need to compute the value of $t$. $(2,4 \sin (\dfrac{t}{2}), 3-\dfrac{t}{\pi} ) \cdot (1,-1,0) =0$ Now, $2-4 \sin (\dfrac{t}{2})=0$ or, $ 2=-4 \sin (\dfrac{t}{2})$ or, $t=\dfrac{\pi}{3}$
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