Answer
$a(0)=10T +6N$
Work Step by Step
$v(t)=\dfrac{dr}{dt}=(6t+3) i +(4+8t) j +6 \sin t k$
and $a(t)=\dfrac{dv(t)}{dt}=6 i+8 j +6k \cos t$
$|a(t)|=2 \sqrt {9 \cos^2 t +25} $
and $ |a(0)|=2 \sqrt {9 \cos^2 (0) +25} =2\sqrt {9+25}=2 \sqrt {34}$
and $a_{T}(0)=10$
Now, $a_{N}=\sqrt {|a(0)|^2 -a^2_{T} (0)}=\sqrt {(2 \sqrt {34})^2 -(10)^2}=6$
So, $a(0)=a_T(0) T+a_{N} N=10T +6N$
