University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.2 - Vectors - Exercises - Page 609: 41

Answer

$a=\dfrac{3}{2}$ and $b=\dfrac{1}{2}$

Work Step by Step

Suppose $u=2i+j,v=i+j,w=i-j$ The scalars $a,b$ can be found as: $u=av+bw$ Thus, $2i+j=ai+aj+bi-bj$ or, $a+b=2; a-b=1$ After solving the above two equations, we have $2a=3 \implies a=\dfrac{3}{2}$ From equation $a+b=2 \implies \dfrac{3}{2}+b=2$ or, $b=\dfrac{1}{2}$ Hence, $a=\dfrac{3}{2}$ and $b=\dfrac{1}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.