University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.2 - Vectors - Exercises - Page 609: 40



Work Step by Step

Since, we have $\overrightarrow{AB}=-7i+3j+8k$,$A=(-2,-3,6)$ and suppose $B=(p,q,r)$ $\overrightarrow{AB}=(p+2)i+(q+3)j+(r-6)k=-7i+3j+8k$ Now, $p+2=-7, q+3=3, r-6=8$ Thus, $p=-9,q=0,r=14$ Hence, $B=(-9,0,14)$
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