Answer
$x^2+(y +7)^2+z^2=49$
Work Step by Step
We know that the standard equation of a sphere is written as:
$(x-x_0)^2+(y-y_0)^2+(z-z_0)^2=r^2\ \ \ $ (1)
Here, $(x_0,y_0,z_0)$ represents the center and $r$ is the radius of the sphere.
Since, we have $x_0=0,y_0=-7,z_0=0, r=7$
Plug all the above values in equation (1), then we get
Thus, $(x - 0)^2+(y -(-7))^2+(z -0)^2=(7)^2$
Hence, $x^2+(y +7)^2+z^2=49$
