## University Calculus: Early Transcendentals (3rd Edition)

$x=3,y=-1,z=2$
Definition: Consider the point $(x_0,y_0,z_0)$ on the plane. The plane is passing through the point $(x_0,y_0,z_0)$ and is perpendicular to the x-axis, y-axis, and z-axis, so $x=x_0,y=y_0$ and $z=z_0$ Thus, we have $x=3,y=-1,z=2$