Answer
$ \lt \dfrac{-1}{3}, \dfrac{-1}{3},\dfrac{-1}{3}\gt$
Work Step by Step
The formula to calculate the vector projection of $u$ onto $v$ is given by: $proj_{v}u=(\dfrac{u \cdot v}{v \cdot v})v$
Now,
$proj_{v}u=\dfrac{1(1)+(-2)(1)+(0)(-1)}{2(2)+1(1)+(1)(1)}\lt 1,1,1 \gt=\dfrac{-1}{3}\lt 1,1,1 \gt$
Thus, our final answer is: $ \lt \dfrac{-1}{3}, \dfrac{-1}{3},\dfrac{-1}{3}\gt$
