Answer
$\sqrt {14}$
Work Step by Step
The formula to calculate the distance for two vectors is given by:
$d=\dfrac{|u \cdot v|}{|v|}$
Thus, we have $u \cdot v=-2(2)+(0)(3)+(-10)(1)=-14$
and $|u \cdot v|=|-14|=14$
Now, $d=\dfrac{|u \cdot v|}{|v|}=\dfrac{14}{ \sqrt {(2)^2+(3)^2+(1)^2}}=\dfrac{14}{\sqrt {14}}=\sqrt {14}$
