Answer
$r=-4 \cos \theta$
Work Step by Step
Here, we have $x^2+y^2+4x=0$
This implies that
$(x+2)^2+y^2=4$
Thus, we have an equation of a circle with center $(-2,0)$ and radius $2$
So, $r^2+4r \cos \theta=0$
Hence, $r=-4 \cos \theta$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 10 - Practice Exercises - Page 594: 36
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
