University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Practice Exercises - Page 594: 36


$r=-4 \cos \theta$

Work Step by Step

Here, we have $x^2+y^2+4x=0$ This implies that $(x+2)^2+y^2=4$ Thus, we have an equation of a circle with center $(-2,0)$ and radius $2$ So, $r^2+4r \cos \theta=0$ Hence, $r=-4 \cos \theta$
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