## University Calculus: Early Transcendentals (3rd Edition)

$$y=e^{5t}+b$$ on condition that $y\gt b$.
To solve natural logarithm equations, keep in mind this property: - If $\ln x = \ln a$ then $x=a$ $$\ln (y-b)=5t$$ - Condition: $y\gt b$ - Recall the property: $\ln e^x=x$ That means $5t=\ln e^{5t}$ Therefore, $$\ln(y-b) = \ln e^{5t}$$ $$y-b=e^{5t}$$ $$y=e^{5t}+b$$