Answer
$3.71728$
Work Step by Step
Here, we have $\int dy=\int 2xe^{x^2} dx$
Now, $y=e^{x^2}+c$
Further, apply the initial conditions.
$2=e^{(0^2)}+c$
or, $c=1$
Thus, $y=e^{x^2}+c \implies y=e^{x^2}+1$
Therefore,
$y(1)=e^{(1)^2}+1 =e+1 \approx 3.71728$