Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 8: Techniques of Integration - Practice Exercises - Page 518: 49

Answer

$\overline{T}=25^{\circ} F$ and $n=4$

Work Step by Step

Consider the average value of temperature as follows: $\overline{T}=\dfrac{1}{360-0} \int_0^{365} [37 \sin (\dfrac{2 \pi}{365})(x-101))+25] dx$ Applying Simpson's Rule, now we will plug in the above equation $a=0; b=365$ Suppose that $n=4$ So, we get $\overline{T}=25^{\circ} F$. This means that for this average value of temperature, the value of $n=4$ is sufficient. So, $\overline{T}=25^{\circ} F$ and $n=4$
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