Answer
$$ y = \frac{{\ln 3 + \ln (\ln x)}}{{\ln 3}} $$
Work Step by Step
$$\eqalign{
& {3^y} = 3\ln x \cr
& {\text{take the natural logarithm on both sides}} \cr
& \ln {3^y} = \ln \left( {3\ln x} \right) \cr
& {\text{use power property for logarithms}} \cr
& y\ln 3 = \ln \left( {3\ln x} \right) \cr
& {\text{solve for }}y \cr
& y = \frac{{\ln \left( {3\ln x} \right)}}{{\ln 3}} \cr
& y = \frac{{\ln 3 + \ln (\ln x)}}{{\ln 3}}} $$
