Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 6: Applications of Definite Integrals - Section 6.5 - Work and Fluid Forces - Exercises 6.5 - Page 348: 7

Answer

$780 J$

Work Step by Step

Hooke's Law states that $F=k x$ Use formula: $\int x^n=\dfrac{x^{n+1}}{n+1}+C$. This implies that $W=\int_0^{(50)} (0.624) (x)=(0.312)[ \dfrac{x^2}{2}]_0^{(50)}$ Hence, $(0.312)[ 2500-0] =780 J$
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