Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 6: Applications of Definite Integrals - Section 6.3 - Arc Length - Exercises 6.3 - Page 336: 17

Answer

$9.2 9357$

Work Step by Step

The formula to calculate the arc length is as follows: $L=\int_{c}^{d} \sqrt {1+[f'(x)]^2} dx$ Now, $f'(x)=y+1$ Re-write the equation as follows: $L=\int_{-1}^{3} \sqrt {1+(y+1)^2} dy$ After calculations with a calculator: $l= 9.2 9357$
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