Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises 5.5 - Page 295: 22



Work Step by Step

Let u=$sin x=>du=cosxdx$ =$\int \sqrt{sinx}(1-sin^2x)cosxdx$ =$\int (u^{1/2}-u^{5/2})du$ =$\frac{2}{3}u^{3/2}-\frac{2}{7}u^{7/2}+C$
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