Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.4 - Concavity and Curve Sketching - Exercises 4.4 - Page 214: 93

Answer

See table and explanations.

Work Step by Step

See table. (i) Point $P:$ $f'\lt0$ because of the negative tangent line slope, $f''\gt0$ because of concave up. (ii) Point $Q:$ $f'\gt0$ because of the positive tangent line slope, $f''=0$ because of inflection point. (iii) Point $R:$ $f'\gt0$ because of the positive tangent line slope, $f''\lt0$ because of concave down. (iv) Point $S:$ $f'=0$ because of the maximum at the point, $f''\lt0$ because of concave down. (v) Point $T:$ $f'\lt0$ because of the negative tangent line slope, $f''\lt0$ because of concave down.
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