Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.9 - Linearization and Differentials - Exercises 3.9 - Page 174: 10

Answer

$L(x)=x+1$

Work Step by Step

Step 1. $f(x)=1+x$, $f'(x)=1$, Step 2. Choose $x=8$, $f(8)=9$, $f'(8)=1$, Step 3. The linearization at $x=8$ is $L(x)=f(8)+f'(8)(x-8)=9+(x-8)=x+1$
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