Answer
cos y cot y.
Work Step by Step
Differentiating terms with respect to x, we get
$\frac{dx}{dx}= \frac{d}{dx}$(sec y)
Or 1= sec y tan y•$\frac{dy}{dx}$
which implies that $\frac{dy}{dx}= \frac{1}{sec y tan y}$= cos y cot y.
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.7 - Implicit Differentiation - Exercises 3.7 - Page 155: 9
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