Answer
(20, 30) and 𝛿 =4
Work Step by Step
Solve the inequality |f(x) -L| < e
|$\frac{120}{x}$ -5| <1
-1 0;
Now we need to find the value of 𝛿>0 that places the open interval
(24-𝛿, 24+𝛿) centered at 24 inside the interval (20,30). distance between 24 and 20 is 4 and distance between 24 and 30 is 6. so we will take the smaller value for 𝛿, so 𝛿 =4
