Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.2 - Limit of a Function and Limit Laws - Exercises 2.2 - Page 56: 6


See proof below.

Work Step by Step

Since $\lim\limits_{x \to 1^+}\frac{1}{x-1}=+\infty $ and $\lim\limits_{x \to 1^-}\frac{1}{x-1}=-\infty $ The left-hand and right-hand limits do not match, so the limit does not exist.
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